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For `CE` transistor amlifier, the audio signal voltage across the collector resistance of `2 k Omega` is `4V`. If the currents amplification factor of the transistor is `100` and the base resistance is `1 k Omega`, then the input signal voltage isA. `30 mV`B. `15 mV`C. `10 mV`D. `20mV` |
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Answer» Correct Answer - D `beta=100, V_(0)=4V, R_(i)=10^(3) Omega`, `R_(0)=2xx10^(3) Omega, V_(i)=?` `(V_(0))/(V_(i))=beta(R_(0))/(R_(i)) implies 4/(V_(i))=100xx(2xx10^(3))/(10^(3))` `implies V_(i)=20 mV` |
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