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For complete combustion of ethanol, C_(2) H_(5) OH_((l)) + 3O_(2(g)) to 2CO_(2(g)) + 3H_(2) O_((l)), the amount of heat produced as measured in bomb calorimeter is 1364.47 "kJ mol"^(-1) at 25°C. Assuming ideality the Enthalpy of combustion, Delta_(C) H, for the reaction will be : (R= 8.314 "kJ mol"^(-1) ) |
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Answer» `-1460.50 "kJ mol"^(-1)` `Delta U = - 1364.47 "kJ mol"^(-1)` `Deltan_(g) = -1` `DeltaH = Delta U + Deltan_(g) RT` `= -1364.47 - (1xx 8.314 xx 298)/( 1000)` `=-1366.93 "kJ mol"^(-1)` |
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