1.

For component of vector →P=^i+2^j−3^k values are in column - II, then the correct match is:Column IColumn IIa)X-axisp)1b)Along vectorq)√14→q=^i+2^j+53^kc)Along vectorr)0→r=2^i+4^j−6^kd)Along vectors)√7→s=^i+2^j−3^k√14

Answer»

For component of vector →P=^i+2^j−3^k values are in column - II, then the correct match is:

Column IColumn IIa)X-axisp)1b)Along vectorq)√14→q=^i+2^j+53^kc)Along vectorr)0→r=2^i+4^j−6^kd)Along vectors)√7→s=^i+2^j−3^k√14


Discussion

No Comment Found

Related InterviewSolutions