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For converting a solution if 100 ml KCl of 0.4 M concentration into a solution of KCl 0.05 M concentration. The quantity of water added isA. 900 mlB. 700 mlC. 500 mlD. 300 ml |
Answer» Correct Answer - B We know that, `M_(1)V_(1)= M_(2)V_(2)` `0.05xx V_(1)=0.4xx100` `therefore V_(1)=(0.4xx100)/(0.05)=800` `V_(2)-V_(1)=800-100 rArr 700 ml`. |
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