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For decolourisation of `1 "mol of" KMnO_(4)`, the moles of `H_(2)O_(2)` required isA. `1//2`B. `3//2`C. `5//2`D. `7//2` |
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Answer» Correct Answer - C `2KMnO_(4)+3H_(2)SO_(4)rarrK_(2)SO_(4)+2MnSO_(4)+3H_(2)O+5[O]H_(2)O_(2)+OrarrH_(2)O+O_(2)xx5` Thus 1 mole of acidified `KMnO_(4)` requires 5/2 moles of `H_(2)O_(2)` for decolourisation. |
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