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For each binary operation ** defined below, determine whether ** is commutative or associative on Z, define a**b=a-b |
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Answer» SOLUTION :Since `1-2ne2-1, 1**2 ne 2**1` `therefore ** ` is not COMMUTATIVE Since `(2-4)-5ne2-(4-5), `(2**4)**5 ne 2**(4**5)` `therefore **` is not associative |
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