For each of the following polynomial, find p(1), p(0) and p(- 2).p(y)

1.	For each of the following polynomial, find p(1), p(0) and p(- 2).p(y) = x4 – 2x2 + x
Answer» p(x) = x⁴ – 2x² – x ∴ p(1) = (1)⁴ – 2(1)² – 1 = 1 – 2 – 1 ∴ p(1) = -2 ∴ p(x) = x⁴ – 2x² – x ∴ p(0) = (0)⁴ – 2(0)² – 0 = 0 – 0 – 0 ∴ p(0) = 0 p(x) = x⁴ – 2x² – x ∴ p(-2) = (-2)⁴ – 2(-2)² – (-2) = 16 – 2(4) + 2 = 16 – 8 + 2 ∴ p(-2) = 10

For each of the following polynomial, find p(1), p(0) and p(- 2).p(y) = x4 – 2x2 + x

Answer»

p(x) = x⁴ – 2x² – x

∴ p(1) = (1)⁴ – 2(1)² – 1

= 1 – 2 – 1

∴ p(1) = -2

∴ p(x) = x⁴ – 2x² – x

∴ p(0) = (0)⁴ – 2(0)² – 0

= 0 – 0 – 0

∴ p(0) = 0

p(x) = x⁴ – 2x² – x

∴ p(-2) = (-2)⁴ – 2(-2)² – (-2)

= 16 – 2(4) + 2

= 16 – 8 + 2

∴ p(-2) = 10