For each of the non-perfect cubes in 243 find the smallest number by w

1.	For each of the non-perfect cubes in 243 find the smallest number by which it must be(a) Multiplied so that the product is a perfect cube.(b) Divided so that the quotient is a perfect cube.
Answer» (a) Multiplied so that the product is a perfect cube. 243 = 3 × 3 × 3 × 3 × 3 = 3³ × 3² Hence, to make it a perfect cube we should multiply it by 3. (b) Divided so that the quotient is a perfect cube. 243 = 3 × 3 × 3 × 3 × 3 = 3³ × 3² Hence, to make it a perfect cube we have to divide it by 9.

For each of the non-perfect cubes in 243 find the smallest number by which it must be(a) Multiplied so that the product is a perfect cube.(b) Divided so that the quotient is a perfect cube.

Answer»

(a) Multiplied so that the product is a perfect cube.

243 = 3 × 3 × 3 × 3 × 3

= 3³ × 3²

Hence, to make it a perfect cube we should multiply it by 3.

(b) Divided so that the quotient is a perfect cube.

243 = 3 × 3 × 3 × 3 × 3

= 3³ × 3²

Hence, to make it a perfect cube we have to divide it by 9.