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For `[FeF_(6)]^(3-) and [CoF_(6)]^(3-)`, the statement that is correct is :A. both are colouredB. both are colourlessC. `[FeF_(6)]^(3-)` is colored and `[CoF_(6)]^(3-)` is colorlessD. `[FeF_(6)]^(3-)` is colorless and `[CoF_(6)]^(3-)` is colored |
Answer» Correct Answer - D | |