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For given circuit charge on capacitor C, and `C_(2)` in steady state will be equal to A. `C_(1) (V_(A) - V_(c )), (V_(c ) - V_(B))` respectivelyB. `C_(1) (V_(A) - V_(B)), C_(2) (V_(A) - V_(B))` respectivelyC. `(C_(1) + C_(2)) (V_(A) - V_(B))` on each capacitorD. `((C_(1)C_(2))/(C_(1) + C_(2))) (V_(A) - V_(B))` on each capacitor |
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Answer» Correct Answer - A No current will flow through the resistance at steady state. |
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