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For ground to ground projectile motion equation of path is `y=12x-3//4x^(2)`. Given that `g=10ms^(-2)`. What is the range of the projectile ?A. `36m`B. `30.6m`C. `16m`D. `12.4m` |
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Answer» Correct Answer - C `y=xtantheta(1-(x)/(R))y=(12x)(1-(x)/(16))` `rArr `Range `=16m Ans.` |
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