For hydrogen atom, Rydberg constant (R_(H)) is xm^(-1). Then for He^(+) ion, the corresponding value of this constant will be

For hydrogen atom, Rydberg constant (R_(H)) is xm^(-1). Then for He^(+

1.	For hydrogen atom, Rydberg constant (R_(H)) is xm^(-1). Then for He^(+) ion, the corresponding value of this constant will be
Answer» `x cm^(-1)` `400 x cm^(-1)` `4X cm^(-1)` `0.04 x cm^(-1)` Solution :`bar(V) =((1)/(n_(1)^(2)) - (1)/(n_(2)^(2))) Z^(2) and x m^(-1) = 0.01 x cm^(-1)` For H atom, `bar(v) = 0.01 x ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2))) cm^(-1) " " ( :' Z = 1)` For `He^(+), bar(v) = 0.01 x ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2))) xx 2^(2) cm^(-1) " " ( :' Z = 2)` `= 0.04 x ((1)/(n_(1)^(2)) - (1)/(n_(2)^(2))) cm^(-1)` Hence, `R = 0.04 x cm^(-1)`