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For increase in internal energy of a system is equal to the work done on the system. Which process does the system undergo ? |
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Answer» Isothermal `DeltaQ=DeltaU+DeltaW` Here `DeltaU=-DeltaW` `therefore DeltaQ=-DeltaW+DeltaW` `therefore DeltaQ=0` Therefore, the PROCESS is adiabatic. |
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