1.

For increase in internal energy of a system is equal to the work done on the system. Which process does the system undergo ?

Answer»

Isothermal
Isochoric
Isobaric
Adiabatic

Solution :From FIRST LAW of thermodynamics,
`DeltaQ=DeltaU+DeltaW`
Here `DeltaU=-DeltaW`
`therefore DeltaQ=-DeltaW+DeltaW`
`therefore DeltaQ=0`
Therefore, the PROCESS is adiabatic.


Discussion

No Comment Found