For metal sulphide K_(sp) of CuS, CdS, ZnS and MnS respectively 1 xx 10^(-44), 1 xx 10^(-28), 1 xx 10^(-22) and 1 xx 10^(-14) one mixture of solution of Cu^(2+), Cd^(2+) and Mn^(2+). In this solution H_2S gas passed than which one precipitate last.

For metal sulphide K_(sp) of CuS, CdS, ZnS and MnS respectively 1 xx 1

1.	For metal sulphide K_(sp) of CuS, CdS, ZnS and MnS respectively 1 xx 10^(-44), 1 xx 10^(-28), 1 xx 10^(-22) and 1 xx 10^(-14) one mixture of solution of Cu^(2+), Cd^(2+) and Mn^(2+). In this solution H_2S gas passed than which one precipitate last.
Answer» Solution :The salt which has LEAST `K_(sp)` is first form precipitate with `S^(-2)`. So according to this first of all PRECIPITATION CdS take place. The salt which has MAXIMUM `K_(sp)` It form precipitation at LAST. So the precipitation of MnS take plact at last.