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For motion of an object along the x-axis the velocity `v` dipends on the displacement `x` an `v=3x^(2)`, then what is the acceleration at `x=2 m`.A. `48 ms^(-2)`B. `80 ms^(-2) m`.C. `18 ms^(-2)`D. `10 ms^(-2)` |
Answer» Correct Answer - B Given `v=3x^(2)-2x`, differentiating `v`, we get `(dv)/(dt) =(6x -2) (dx)/(dt) =(6x -2) v` ` rArr a =(6xx 2 -2 ) (3x^(2)-2x)` Now put `x=2 m` `rArr a =(6 xx 2-2) (3(2)^(2)-2xx2)=80 ms^(-2)`. |
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