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For N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g), show that K_(c)=K_(p)(RT)^(2). |
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Answer» Solution :For `N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g)` But PV = NRT, `P=(n/v)RT`, i.e., P = CONCENTRATION `xx` RT `P_(NH_(3))=[NH_(3)]RT," "p_(n_(2))=[N_(2)]RT," "p_(H_(2))=[H_(2)]RT," "K_(p)=(p_(NH_(3))^(2))/(p_(N_(2))*p_(H_(2))^(3))` `thereforeK_(p)=({[NH_(3)]RT}^(2))/({[N_(2)]RT}{[H_(2)]RT}^(3))=([NH_(3)]^(2))/([N_(2)][H_(2)]^(3))xx((RT)^(2))/((RT)(RT)^(3))` `K_(p)=K_(c)*(RT)^(-2)""thereforeK_(c)=K_(p)(RT)^(2)`. |
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