For nge 2, " let "a_(n)=Sigma_(r=0)^(n) (1)/(C_(r)^(2)),then value of b_(n)=Sigma_(r=1)^(n) (1)/(r^(2)C_(r)^(2)) equals……(where C_(r) denotes ""^(n)C_(r)).

For nge 2, " let "a_(n)=Sigma_(r=0)^(n) (1)/(C_(r)^(2)),then value of

1.	For nge 2, " let "a_(n)=Sigma_(r=0)^(n) (1)/(C_(r)^(2)),then value of b_(n)=Sigma_(r=1)^(n) (1)/(r^(2)C_(r)^(2)) equals……(where C_(r) denotes ""^(n)C_(r)).
Answer» `(1)/(n^(2))a_(n)` `(1)/(n^(2))a_(n-1)` `a_(n)` `a_(n)^(2)` Solution :`R_(3)rarrR_(3)cosbetaR_(1)+sinbetaR_(2)` `F(alpha,BETA)=\|{:(COSALPHA,-sinalpha,,""1,),(sinalpha,cosalpha,,""1,),(0," "0,,1-cosbeta+sinbeta,):}\|=1-cosbeta+sinbeta`

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For nge 2, " let "a_(n)=Sigma_(r=0)^(n) (1)/(C_(r)^(2)),then value of b_(n)=Sigma_(r=1)^(n) (1)/(r^(2)C_(r)^(2)) equals……(where C_(r) denotes ""^(n)C_(r)).

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