1.

For NH_(4)HS(s)hArrNH_(3)(g)+H_(2)S(g) reaction started only with NH_(4)HS(s), the observed pressure for reaction mixture in equilibrium is 1.2 atm at 106^(@)C. What is the value of K_(p) for the reaction?

Answer»

`1.44atm^(2)`
`0.36atm^(2)`
`0.16atm^(2)`
`3.6atm^(2)`

Solution :`NH_(4)HS(s)hArrNH_(3)(G)+H_(2)S(g)`
`P P`
`2P=1.2`
`P=0.6`
`K_(p)=P^(2)=(0.6)^(2)=0.36 ATM^(2)`


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