For nitrogen a = 1.4 L^(2) atm, mol^(-2), b = 0.04 L mol^(-1). Find out the diameter of nitrogen molecule.

For nitrogen a = 1.4 L^(2) atm, mol^(-2), b = 0.04 L mol^(-1). Find ou

1.	For nitrogen a = 1.4 L^(2) atm, mol^(-2), b = 0.04 L mol^(-1). Find out the diameter of nitrogen molecule.
Answer» Solution :`b = 4 xx (4)/(3) pir^(3) xx N` b = 0.04 L `mol^(-1) = 40 "CC" mol^(-1)` `40 = 4 xx (4)/(3) xx (22)/(7) xx r^(3) xx 6.023 xx 10^(23)` `r^(3) = 4 xx 10^(-24)` cm , `r = 1.58 A^(@)` Diameter of nitrogen MOLECULE ` = 1.58 xx2 = 3.16 A^(@)`