1.

For oneatom the energydifferencebetweenexcitedstategroundstateis 4.4 xx 1 0^(-4)JThen what willbe wavelengthof photon ?

Answer»

`2.26 xx 10^(12) m`
`1.13 xx 10^(12) m`
`4.25 xx 10^(12)m`
`4.52 xx 10^(12)m`

Solution :`DELTA E = (hc )/(LAMBDA)`


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