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For silver metal, threshold frequency is `1.1 xx 10^(17) s^(-1)`. What is the maximum kinetic energy of the photoelectrons prodcued by shining ultraviolet light of wavelength 1.5 nm on the metal? (Given h = `6.6 xx 10^(-34) J-s, C = 3 xx 10^(8) m//s`]A. `5.94 xx 10^(-17) J`B. `2 xx 10^(-16) J`C. `1 xx 10^(-17) J`D. `8 xx 10^(-15) J` |
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Answer» Correct Answer - A `E_("subjected")=hv_(0)+KE` `thereforeKE = 6.6 xx10^(-34)xx[(3xx10^(8))/(1.5 xx 10^(-9))-1.1xx10^(17)]` `= 5.94 xx10^(-17)J` |
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