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For stationary waves produced in a string of length I wavelength in the n^(th) mode is ...... |
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Answer» `(n ^(2))/(2L)` At `x =l,` we always have `y=0` (nodal point) `thereofre 0= 2a sin (kl) cos (omega t)` `THEREFORE sin (kl) =0` But `sin (npi) =0` (Where `n = 1,2,3,…)` `therefore kl = n PI` `therefore (2pi)/(LAMDA)l = npi` `therefore lamda = (2l)/(n) ` (Where `n ne 0 (n = 1,2,3,...)}` |
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