For testing `SO_(4)^(2-)` with `BaCl_(2)` solution why should sodium carbonate not be acidified with too much of conc. HCl.

For testing `SO_(4)^(2-)` with `BaCl_(2)` solution why should sodium c

1.	For testing `SO_(4)^(2-)` with `BaCl_(2)` solution why should sodium carbonate not be acidified with too much of conc. HCl.
Answer» In the presence of conc. HCl, `BaCl_(2)` itself will be precipitated the precipitated `BaCl_(2)` is mistaken as `BaSO_(4)`

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For testing `SO_(4)^(2-)` with `BaCl_(2)` solution why should sodium carbonate not be acidified with too much of conc. HCl.

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