For the below graph which of the following combination is correct, (n represents mole and P represent pressure) (I) If n is constant throughout then P at 2nd point must be greater than at 1st point. (II) If n is doubled in moving from 1st point to 2nd point then P also doubles in the process. (III) If n is constant then P is maximum at point (1). A. I is trueB. II is trueC. Both II and III are trueD. I, II and III all are correct

For the below graph which of the following combination is correct, (n

1.	For the below graph which of the following combination is correct, (n represents mole and P represent pressure) (I) If n is constant throughout then P at 2nd point must be greater than at 1st point. (II) If n is doubled in moving from 1st point to 2nd point then P also doubles in the process. (III) If n is constant then P is maximum at point (1). A. I is trueB. II is trueC. Both II and III are trueD. I, II and III all are correct
Answer» Correct Answer - A

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If an element can exist in several oxidation states, it is convenient to display the reduction potentials corresponding to the various half reactions in diagrammatic from, known as Latimer diagram. The Latimer diagram for chlorine in acid solution is `Cl_(4)^(-)overset(+1.20V)toClO_(3)^(-)overset(+1.60V)toClO_(2)^(-)overset(+1.60V)to` `ClO^(-)overset(+1.67V)toCl_(2)overset(+1.36V)toCl^(-)` In basic solution is : `ClO_(4)^(-)overset(+0.37V)toClO_(3)^(-)overset(+0.30V)toClO_(2)^(-)overset(+0.68)to` `ClO^(-)overset(+0.42V)toCl_(2)overset(+1.36)toCl^(-)`. The standard potentials for two nonadjacent species can also be calculated by using the concept that `DeltaG^(@)` is an additive property but using potential is not an assitive property and `DeltaG^(@)=-nFx^(0),` If a given oxidation state is a the next higher oxidation state disproportionation can occur. The reverse of relative stabilities of the oxidation state can also be understood by drawing a graph of `DeltaG^(@)//F` against oxidation state, known as Frost diagram, Choosing the stability of zero oxidation state arbitrery as zero. The most stable oxidation state of a apecies lies lowest in the digram Disproportionation is spontaneous if the species lies above a straight line joining its two product species. For a hypothetical element, the Frost diagram is shown in figure Which of the following oxidation state is least stable ?A. -1B. 0C. 2D. 3
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