For the cell reaction, `2Cr^(4+)+Coto2Ce^(3+)+Co^(2+)" "E_((cell))^(@)` is 1.89V and `E_(Co//Co^(2+))^(@)=-0.028`. If `E_(Ce^(4+)//Ce^(3+))^(@)`A. `-1.64V`B. `+1.64V`C. `-2.08V`D. `+2.17V`

For the cell reaction, `2Cr^(4+)+Coto2Ce^(3+)+Co^(2+)" "E_((cell))^(@)

1.	For the cell reaction, `2Cr^(4+)+Coto2Ce^(3+)+Co^(2+)" "E_((cell))^(@)` is 1.89V and `E_(Co//Co^(2+))^(@)=-0.028`. If `E_(Ce^(4+)//Ce^(3+))^(@)`A. `-1.64V`B. `+1.64V`C. `-2.08V`D. `+2.17V`
Answer» Correct Answer - B In this cell Co is oxidised and it acts as anode and Ce acts as cathode. `E_(Cell)^(@)=E_("cathode")^(@)-E_("anode")^(@)=1.89=E_(Cell)^(@)-(-0.28)` `E_(Cell)^(@)=-1.89-0.28=1.61`volt.

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For the cell reaction, `2Cr^(4+)+Coto2Ce^(3+)+Co^(2+)" "E_((cell))^(@)` is 1.89V and `E_(Co//Co^(2+))^(@)=-0.028`. If `E_(Ce^(4+)//Ce^(3+))^(@)`A. `-1.64V`B. `+1.64V`C. `-2.08V`D. `+2.17V`

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