For the cell reaction , |Cu| Cu^(2+)(aq)|Ag^(+)|Ag is E^(@) Cu^(2)|Cu=+0.34 V adb nE^(@) Ag^(+) |Ag=0.80 V and [Cu^(+2)]=0.01 and [Ag^(+)] = 1.0 "mol dm"^(-3) the emf of the cell is

For the cell reaction , |Cu| Cu^(2+)(aq)|Ag^(+)|Ag is E^(@) Cu^(2)|Cu=

1.	For the cell reaction , \|Cu\| Cu^(2+)(aq)\|Ag^(+)\|Ag is E^(@) Cu^(2)\|Cu=+0.34 V adb nE^(@) Ag^(+) \|Ag=0.80 V and [Cu^(+2)]=0.01 and [Ag^(+)] = 1.0 "mol dm"^(-3) the emf of the cell is
Answer» 0.34 V 0.46 V 0.52 V 1.14 V Solution :`E_("cell")=E_("cell")^(@)+(0.059)/(2)"log"([AG^(+)])/([CU^(+2)])` `=0.80-0.34+(0.059)/(2)"log"((1.0)^(2))/(0.01)` `=0.46 +(0.059)/(2) xx 2=0.46+0.059` =0.52 V