For the cell, `TI|TI^(+)(0.001M)|Cu^(2+)(0.1M)|Cu,E_(cell)` at `25^(@)C` is 0.83 V. this can be increasedA. by increasing `[Cu^(2+)]`B. by increasing `[TI^(+)]`C. by decreasing `[Cu^(2+)]`D. by decreasing `[TI^(+)]`

For the cell, `TI|TI^(+)(0.001M)|Cu^(2+)(0.1M)|Cu,E_(cell)` at `25^(@)

1.	For the cell, `TI\|TI^(+)(0.001M)\|Cu^(2+)(0.1M)\|Cu,E_(cell)` at `25^(@)C` is 0.83 V. this can be increasedA. by increasing `[Cu^(2+)]`B. by increasing `[TI^(+)]`C. by decreasing `[Cu^(2+)]`D. by decreasing `[TI^(+)]`
Answer» Correct Answer - A::D `2TI+Cu^(2+)to2TI^(+)+Cu,E_(cell)-E_(cell)^(@)-(0.0591)/(2)"log"([TI^(+)]^(2))/([Cu^(2+)])`

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For the cell, `TI|TI^(+)(0.001M)|Cu^(2+)(0.1M)|Cu,E_(cell)` at `25^(@)C` is 0.83 V. this can be increasedA. by increasing `[Cu^(2+)]`B. by increasing `[TI^(+)]`C. by decreasing `[Cu^(2+)]`D. by decreasing `[TI^(+)]`

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