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| 1. |
For the circuit, let us assume that R = 1 Ω, L = 10 H, and V(t) = 10 cos (1000 + 30°)V and the differential equation for I() is given by |
| Answer» Replacing current and voltage by their phasors I and 10ejp/b, resp. and by jω = j1000, we obtain the phasor equation I + 10-3(j1000I) = 10ejp/6 or I(1 + j1) = 10ejp/6 Having determined the value of I, we now find the required solution to be I(t) = Rc [I ejωt] = Rc[7.07e -jp/2 ej1000t] = 7.07 cos (1000t - 15°)A. | |