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InterviewSolution
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For the coagulation of `10 mL` of `Fe(OH)_(3) sol, 2 mL` of `1 M KBr` is required. What is the flocculation value of `KBr`? |
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Answer» `2mL` of `1MKBr` contans `KBr=(1)/(1000)xx2mol=2m mol` Thus, `10mL` of `Fe(OH)_(3)` sol requires `KBr` for complete coagulation `=2m mol` `:. 1L,` i.e., `1000mL,` of the sol requires `KBr` for complete coagulation `=200m mol` Hence, flocculation value of `KBr=200` `2mL` of `1MKBr` contans `KBr=(1)/(1000)xx2mol=2m mol` Thus, `10mL` of `Fe(OH)_(3)` sol requires `KBr` for complete coagulation `=2m mol` `:. 1L,` i.e., `1000mL,` of the sol requires `KBr` for complete coagulation `=200m mol` Hence, flocculation value of `KBr=200` |
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