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InterviewSolution
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For the coagulation of `500mL` of arsenious sulphide sol, `2mL` of `1MNaCl` is required. What is the flocculation value of `NaCl` ? |
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Answer» Correct Answer - 4 2mL of 1M NaCl contains `NaCl=(2)/(1000)=2` mmol Thus 500 mL of `As_(2)S_(3)` sol require NaCl for complete coagulation=2mmol Hence 1L, i.e., 1000 mL of the sol reqruie NaCl for complete coagulation=4mmol Therefore, flocclation value of NaCl=4 |
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