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For the concentration cell `Pt(H_(2)-p_(1))|H^(+)(0.5M)|Pt(H_(2)-P_(2))` the cell reaction will be spontaneous ifA. `p_(1)=p_(2)`B. `p_(1)gtp_(2)`C. `p_(2)gtp_(1)`D. None of these |
Answer» Correct Answer - B `Pt(H_(2)-p_(1))|H^(+)(0.5M)|Pt(H_(2)-p_(2))` it is a concentration cell reversible w.r.t. cation `H_(2)(p_(1))rarr2H^(+)2e^(-)` `2H^(+)+2e^(-)rarrH_(2)(p_(2))` `H_(2)(p_(1))rarrH_(2)(p_(2))` `E_("cell")=-(0.591)/( 2)"log"(p_(2))/(p_(1))` `=(0.0591)/(5) "log"(p_(1))/(p_(2))` `E_("cell")gt0` if `p_(1)gtp_(2)` |
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