1.

For the concentration cell `Pt(H_(2)-p_(1))|H^(+)(0.5M)|Pt(H_(2)-P_(2))` the cell reaction will be spontaneous ifA. `p_(1)=p_(2)`B. `p_(1)gtp_(2)`C. `p_(2)gtp_(1)`D. None of these

Answer» Correct Answer - B
`Pt(H_(2)-p_(1))|H^(+)(0.5M)|Pt(H_(2)-p_(2))`
it is a concentration cell reversible w.r.t. cation
`H_(2)(p_(1))rarr2H^(+)2e^(-)`
`2H^(+)+2e^(-)rarrH_(2)(p_(2))`
`H_(2)(p_(1))rarrH_(2)(p_(2))`
`E_("cell")=-(0.591)/( 2)"log"(p_(2))/(p_(1))`
`=(0.0591)/(5) "log"(p_(1))/(p_(2))`
`E_("cell")gt0` if `p_(1)gtp_(2)`


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