For the cqiuilibrium LiCI 3NH_(3(s)) LiCI NH_(3(s)) + 2NH_(3(g)),Kp = 9 atm^(2) "at" 37^(@)C. A 5 lires vesel contains 0. 1 mole of LiCI NH_(3). How many moles of NH_(3) should be added to the llask at this temperature to derive the backward reaction for completion ?

For the cqiuilibrium LiCI 3NH_(3(s)) LiCI NH_(3(s)) + 2NH_(3(g)),Kp =

1.	For the cqiuilibrium LiCI 3NH_(3(s)) LiCI NH_(3(s)) + 2NH_(3(g)),Kp = 9 atm^(2) "at" 37^(@)C. A 5 lires vesel contains 0. 1 mole of LiCI NH_(3). How many moles of NH_(3) should be added to the llask at this temperature to derive the backward reaction for completion ?
Answer» <P>0.2 0.59 0.69 0.79 Solution :BACKWARD reaction to completion `IMPLIES` 0.1 moles of `4.CI.NH_(3)` is used `implies` 0.2 moles of `NH_(3)` is used after complection, still `K_(P) =9 implies P_(NH_(3)) = 3 implies n_(NH_(3)) = 0.59` `:.` TOTAL moles to be added = 0.2 + 0.59 = 0.79