InterviewSolution
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InterviewSolution
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For the `[Cr(H_(2)O)_(6)]^(2+)` ion, the mean pairing energy P is found to `23500cm^(-1)`. The magnitude of `Delta_(0)` is `13900cm^(-1)`. Calculate the C.F.S.E. `(cm^(-1))` for this complex ion corresponding to high spin state (x) and low spin state (y). Write your answer as `((y-x)/(100))`. |
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Answer» Correct Answer - 96 For a `d^(4)`ion in a high spin state. CFSE`=-0.6Delta_(0)=-0.6xx(13,900 cm^(-1))=-8340 cm^(-1)` For a `d^(4)` ion in a low spin state, the net CFSE is, `=-1.6Delta_(0)+P=-1.6xx(13,900 cm^(-1))+23500 cm^(-1)= +1,260 cm^(-1)` Since `Delta_(0)(=13,900 cm^(-1)) lt P(=23,500 cm^(-1))`, the high spin configuration would be more stable . |
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