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For the curve `y=4x^3-2x^5,`find all the points at which the tangent passes through the origin.A. `(-2,14)`B. `(2,14)`C. `(2,-2)`D. `(-2,2)` |
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Answer» Correct Answer - B::D `(dy)/(dx)` at `x_(1),y_(1)` must equal to `(y_(1)-0)/(x_(1)-0)` Therefore `2x_(1)+3=(x_(1)^(2)+3x_(1)+4-0)/(x_(1)-0)` Hence `x_(1)^(2)=4impliesx_(1)=+-2impliesy_(1)=14,2` `(2,14),(-2,2)`s |
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