1.

For the damped oscillator, the mass m of the block is 200g, k = 90 Nm^(-1) and the damping constant b is 40 gs^(-1). Calculate the period of oscillation.

Answer»

Solution :`SQRT(km) = sqrt(90xx0.2)`
`sqrt(18)= 4.2426 APPROX 4.243 kgs^(-1)" and "b = 0.04 kgs^(-1)`
`THEREFORE b lt lt sqrt(km)`
The time period `T= 2PI sqrt((m)/(k))`
`= 2xx3.14 sqrt((0.2)/(90))`
`= 6.28xx 0.471 = 0.296`
`therefore T approx 0.3s`.


Discussion

No Comment Found