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For the decomposition of `H_2O_2(aq)` it was found that `V_(O_2)` (t=15 min) was 100 mL (at `0^@C` and 1 atm) while `V_(O_2)` (maximum) was 200 mL (at `0^@C` and 2 atm). If the same reaction had been followed by the titration method of if `V_(KMnO_(4))^((cM))`(t=0) had been 40 mL, what would `V_(KMnO_(4))^((cM))`(t=15 min) have been ?A. 30 mLB. 25 mLC. 20 mLD. 15 mL |
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Answer» Correct Answer - A `1/4th` reaction has completed upto 15 min.Hence `V_(KMnO_4)` will be `3/4xx40=30` mL |
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