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For the electrochemicl cell, `M|M^(+)||X^(-)|X E_((M^(+)//M))^(@) = 0.44 V` and `E_((X//X^(-)))^(@) = 0.33 V` From this data one can deduce that :A. `M + X rarr M^(+) + X^(-)` is the spontaneous reactionB. `M^(+) + X^(-) rarr M + X` is the spontaneous reactionC. `E_(cell) = 0.77 V`D. `E_(cell) = -0.77 V` |
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Answer» Correct Answer - B `E_(cell) = E_(OP_(M//M^(+)))^(@) + E_(RP_(X//X^(-)))^(@)` `= -0.44 + 0.33 = -0.11 V` for `M + X rarr M^(+) + X^(-)`. Thus reaction is non-spontaneous. The spontaneous reaction in `M^(+) + X^(-) rarr M + X, E^(@) = 0.11 V` |
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