For the equilibirum, PCl_(5)(g) hArr PCl_(3)(g) + Cl_(2)(g) at 298 K, K = 1.8 xx 10^(-7). Calculate Delta G^(@) for the reaction (R = 8.314 JK^(-1) mol^(-1)).

For the equilibirum, PCl_(5)(g) hArr PCl_(3)(g) + Cl_(2)(g) at 298 K,

1.	For the equilibirum, PCl_(5)(g) hArr PCl_(3)(g) + Cl_(2)(g) at 298 K, K = 1.8 xx 10^(-7). Calculate Delta G^(@) for the reaction (R = 8.314 JK^(-1) mol^(-1)).
Answer» Solution :`PCl_(5)(g) HARR PCl_(3)(g) + Cl_(2)(g), ""K = 1.8 xx 10^(-7)` `Delta G^(@) = -2.303 RT log K = -2.303 xx 8.314 JK^(-1) mol^(-1) xx 298 K xx log(1.8 xx 10^(-7))` `= -2.303 xx 8.314 xx 298[log 1.8 + log10^(-7)] = -19.147 xx 298[0.2553 - 7.000]` `Delta G^(@) = (-19.147 xx 298 xx (-6.7447))/(1000) = +34.48 KJ mol^(-1)`