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For the equilibrium, `2 NOCl (g) hArr 2 N O (g) + Cl_(2) (g),` the value of the equilibrium constant, `K_(c)" is " 3.75 xx 10^(-6)" at " 1069 K." Calculate " K_(p)` for the reaction at this temperature. |
Answer» For the given reaction , `Delta n = (2+1) - 2 = 1` `K_(p) = K_(c)(RT)^(Delta n) = (3. 75 xx 10^(-6)) ( 0.0831 xx 1069)` `= 3.33 xx 10^(-4)`. |
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