InterviewSolution
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InterviewSolution
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For the equilibrium `2NOCl(g) hArr 2NO(g)+Cl_(2)(g)` the value of the equilibrium constant, `K_(c)` is `3.75 xx 10^(-6)` at `1069 K`. Calcualate the `K_(p)` for the reaction at this temperature? |
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Answer» We know that, `K_(p) = K_(c)(RT)^(Deltan)` For the above reaction, `Deltan = (2+1)-2=1` `K_(p) = 3.75 xx 10^(-6)(0.0831 xx 1069)` `K_(P) = 0.033` |
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