For the following bond cleavages, use curved arrows to show the electron flow and classify each as homolysis or heterolysis. Identify reactive intermediate produced as free radical, carbocation and carbanion (a) CH_(3)O- OCH_(3) rarr CH_(3) overset(.)(O) + overset(.)(O)CH_(3)

For the following bond cleavages, use curved arrows to show the electr

1.	For the following bond cleavages, use curved arrows to show the electron flow and classify each as homolysis or heterolysis. Identify reactive intermediate produced as free radical, carbocation and carbanion (a) CH_(3)O- OCH_(3) rarr CH_(3) overset(.)(O) + overset(.)(O)CH_(3)
Answer» Solution :(a) Type of bond fission: Homolytic The one-one `e^(-)` Form free radicals of O-O bond transfer on O. is `CH_(3)-overset(overset(O)(\|\|))(C )-CH_(3)`. In it the carbanion `-CH_(2)COCH_(3)` is from by heterolytic fission of C-H bond. The transfer of electron pair is as under (c ) In it, the carbocation `(CH_(3)) C^(+)` is formed by heterolytic fission of C-Br bond and or get the electron pair of C-Br bond The electron pair of C-Br bond transfer on Br and form corbocation and `Br^(-)`. (d) The heterolytic fission of `pi` bond in C=C and `E^(+)` get electron pair of `pi`-bond and form carbocation `(C_(6)H_(6)E)^(+)`