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For the following cell `Zn(s)|ZnSO_(4)(aq)||CuSO_(4)(aq)|Cu(s)` when the concentration of `Zn^(2+)` is 10 times the concentration of `Cu^(2+)`, the expression for `DeltaG` (in 1 `mol^(-1)`) is [F is faraday constant, R is gas constant, T is temperature, `E^(@)(cell)=1.1V`]A. `2.303RT+1.1F`B. `1.1F`C. `2.303RT-2.2F`D. `-2.2F` |
Answer» Correct Answer - C Cell reaction is `Zn+Cu^(2+)toZn^(2+)+Cu` `DeltaG=DeltaG^(@)+2.303RTlogQ` `=DeltaG^(@)+2.303RTlog([Zn^(2+)])/([Cu^(2+)])` `DeltaG^(@)=-nFE_(cell)^(@)=-2F(1.1)` `thereforeDeltaG=-2F(1.1)+2.303RTlog10` `=2.303RT-2.2F` |
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