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For the following cell, `Zn(s)|ZnSO_(4)(aq)||CuSO_(4)(aq)|Cu(s)` When the concentration of `Zn^(2+)` is 10 times the concentration of `Cu^(2+)`, the expression for `DeltaG` ( in `Jmol^(-1)`) is [F is faraday constant: R is gas constant, T is temperature, `E^(@)(cell)=1.1V`]A. 2.303RT+1.1FB. 1.1FC. 2.303RT-2.2FD. `-2.2F` |
Answer» Correct Answer - C `DeltaG=DeltaG^(o)+2.303RTlog_(10)Q,Q=([Zn^(2+)])/([Cu^(2+)])` `=-2F(1.1)+2.303RTlog_(10)10` `=2.303RT-2.2F` Given `E_(Cl_(2)//Cl^(-))^(o)=1.36V,E_(Cr^(3+)//Cr)^(o)=-0.74V` `E_(Cr_(2)O_(7)^(2-)//Cr_(3+))^(o)=1.33V,E_(MnO_(4)^(-))^(o)//Mn^(2+)=1.51V` |
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