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For the following equilibrium `PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g)` `K_(p)` is formed to be equal to `K_(x )`. This is attained atA. 1 atmB. 0.5 atmC. 2 atmD. 4 atm |
Answer» Correct Answer - A `K_(p)=K_(x )(P)^(Deltan)` `K_(x)` is equilibrium constant when concentration are take as mole fraction. `K_(p)=K_(x)(P)` `K_(p)=K_(x)` when `P=1` atm |
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