1.

For the following, Kc = 6.3 x 1014 at 100 KNO(g) + O3(g) ⇌ NO2(g) + O2(g)Both the forward and reverse reactions in the equilibrium are elementary bi-molecular reactions. What is Kc, for the reverse reaction?

Answer»

The reaction, NO2(g) + O2(g) ⇌ NO(g) + O3(g) is reverse of the reaction, NO(g) + O3(g) ⇌ NO2(g) + O2(g). Therefore, the equilibrium constant of the former is reciprocal of the latter.

Therefore, K (NO2(g) + O2 ⇌ 2NO(g) + O3(g))

\(\frac{1}{K(NO(g)+O_3(g)\, \rightleftharpoons\, NO_2(g)+O_2(g))}\)

\(\frac{1}{6.3\times 10^{14}}\) = 0.159 x 10-14

= 1.59 x 10-15



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