For the following question, enter the correct numerical value, ( in decimal - notation , truncated //rounded - offto the second decimal place, e.g., 6.50, 7.00, - 0.33, 30.27, - 127.30 )using the mouse and the onscreen virtual numeric keypadin the place designated to enter the answer.

For the following question, enter the correct numerical value, ( in de

1.	For the following question, enter the correct numerical value, ( in decimal - notation , truncated //rounded - offto the second decimal place, e.g., 6.50, 7.00, - 0.33, 30.27, - 127.30 )using the mouse and the onscreen virtual numeric keypadin the place designated to enter the answer.
Answer» Solution :The surface of copper gets TARNISHED by the formation of copper oxide. `N_(2)` gas was passed to prevent the oxide formation during heating of copper at 1250 K. However ,the `N_(2)`gas contains 1 mole `%` of water vapour as impurity . The water vapour oxidize copper as per the reaction given below `:` `2Cu(s) + H_(2)O(g) rarrCu_(2)O(s) + H_(2)(g)` `p_(H_(2))` is the minimumpartal pressure of `H_(2)` ( in bar) NEEDED to prevent the oxidation at 1250 K. The value of In `(p_(H_(2))` is `"................"` ( Given `:` TOTAL pressure `= 1 ` bar, R ( universal gas constant `) = 8 JK^(-1) , mol^(-1)` In `( 100 = 2.3, Cu(s)` and `Cu_(2)O(s)` are MUTUALLY immiscible At `1250 K: 2 Cu(s) + (1)/(2) O_(2)(g) rarr Cu_(2)O(s), DeltaG^(@) = - 78000 J mol^(-1)` `H_(2)(g) + (1)/(2) O_(2)(g) rarr H_(2)O(g) , DeltaG^(@) = - 178000 J mol^(-1)` G is the Gibb's energy )