1.

For the following reaction in equlibrium `PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g)` Vapour density is found to be 100 when 1 mole of `PCl_(5)` is taken in a 10 litre flask at `27^(@)C` Calculate the equlibrium pressure. Also calculate percentage dissociation of `PCl_(3)`

Answer» `PCl_(5) hArr PCl_(3)(g)+Cl_(2)(g)`
`{:("Initial moles",1,0,0),("At equlibrium",1-alpha,alpha, alpha),("Concentration",(1-alpha)/(10),(alpha)/(10),(alpha)/(10)):}`
`D=104.25`
`D=100`
`y=2" "therefore alpha=0.0425or 4.25%`
Total moles at equlibrium `=1+alpha=1+0.0425=1.0425 `
Let total pressure at equlibrium be P atm
`PV=nRT`
`P=(1.0425xx0.282xx300)/(10)=2.57atm`


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