InterviewSolution
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InterviewSolution
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For the fuel cell reaction `2H_(2)(g) +O_(2)(g) rarr 2H_(2)O(l), Deta_(f)H_(298)^(@) (H_(2)O,l) =- 285.5 kJ//mol` What is `Delta_(298)^(@)` for the given fuel cell reaction? Given: `O_(2)(g) +4H^(+)(aQ) +4e^(-) rarr 2H_(2)O(l) E^(@) = 1.23 V`A. `-0.322 J//K`B. `-0.635 kJ//K`C. `3.51 kJ//K`D. `-0.322 kJ//K` |
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Answer» Correct Answer - D `{:(2H_(2) +O_(2) rarr H_(2)O ,DeltaH = 2X - 285.5 kJ),(O_(2)+4H^(+) +4e^(-) rarr 2H_(2)O, E^(@) = 1.23),(2H_(2) rarr 4H^(+) +4e^(-),E^(@) = 0),("for reaction":,),(O_(2) +2H_(2) rarr 2H_(2)O, E^(@) = 1.23):}` `DeltaG^(@) = -nFE^(@) =- 4 xx 96500 xx 1.23 =- 474780` `DeltaG^(@) = DeltaH^(@) - T DeltaS^(@) - 474780 =- 571000 - 298 DeltaS^(@)` `DeltaS^(@) =- 322.8 J//K` |
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