For the given progression, find the 9th term, 2,6, 18, 54

1.	For the given progression, find the 9th term, 2,6, 18, 54
Answer» Here the terms are in G.P I.e.,2,6,18,54 a1=2a2=6a3=18a4=54 a2/a1= 6/2=3 a3/a2=18/6=3 a4/a3=54/18=3 Since ratio is equal, so this is in G.P. To find the nth term in G.P tn = ar^(n-1) Here a=2, r=common ratio=3n = 9 By substituting in Formula we get, 2(3)^(9-1)= 2(3)^8= 2(6561)= 13122 9th term for given series is 13122

Answer»

Here the terms are in G.P

I.e.,2,6,18,54

a1=2a2=6a3=18a4=54

a2/a1= 6/2=3

a3/a2=18/6=3

a4/a3=54/18=3

Since ratio is equal, so this is in G.P.

To find the nth term in G.P tn = ar^(n-1)

Here a=2, r=common ratio=3n = 9

By substituting in Formula we get, 2(3)^(9-1)= 2(3)^8= 2(6561)= 13122

9th term for given series is 13122

Discussion