Saved Bookmarks
| 1. |
For the given reaction, match column l with column ll and mark the correct option from the codes given below.Fe2O3 + xCO → yFe + xCO2Column I Column ll(a) Oxidising agent (i) 2(b) Reducing agent (ii) 3(c) x (iii) Fe2O3(d) y(iv) CO(A) (a)-(iv), (b)-(iii), (c)-(ii), (d)-(i) (B) (a)-(iv), (b)-(lii), (c)-(i), (d)-(ii) (c) (a)-(iii), (b)-(iv), (c)-(ii), (d)-(i) (D) (a)-(iii), (b)-(iv), (c)-(i), (d)-(ii) |
|
Answer» Correct option (c) (a)-(iii), (b)-(iv), (c)-(ii), (d)-(i) Explanation: Balanced chemical equation is Fe2O3 + xCO → yFe + xCO2 Thus, x is 3 and y is 2. ln this reaction, Fe2O3 loses oxygen so, it gets reduced and acts as an oxidising agent while CO gains oxygen so, it gets oxidised and acts as a reducing agent. |
|